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Pass Exam With Full Sureness – Associate-Developer-Apache-Spark Dumps with 179 Questions [Q87-Q106]

Pass Exam With Full Sureness – Associate-Developer-Apache-Spark Dumps with 179 Questions [Q87-Q106]

May 7, 2023 adminAssociate-Developer-Apache-Spark, DatabricksAssociate-Developer-Apache-Spark certification book torrent, Associate-Developer-Apache-Spark dumps cost, Associate-Developer-Apache-Spark latest exam guide materials, Associate-Developer-Apache-Spark latest exam questions fee, Associate-Developer-Apache-Spark questions and answers free, Associate-Developer-Apache-Spark test resultLeave a Comment on Pass Exam With Full Sureness – Associate-Developer-Apache-Spark Dumps with 179 Questions [Q87-Q106]

Pass Exam With Full Sureness – Associate-Developer-Apache-Spark Dumps with 179 Questions

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Why you should take Databricks Associate Developer Apache Spark Exam?

If you are a developer who is interested in learning more about Spark and Big Data technologies, then you should definitely consider taking the Databricks Associate Developer Apache Spark Exam. This exam will help you learn how to use the technologies that are being used in the real world. Databricks Associate Developer Apache Spark exam dumps are the best way to prepare for this exam.

Today’s modern businesses need to be agile and nimble to adapt to the fast-paced business environment. With the advent of big data, cloud computing, and the Internet of Things, enterprises now face the challenge of managing, processing, analyzing, and integrating vast amounts of data. These challenges require new skills and a new approach to problem solving. The Apache Spark is a high-performance analytics engine that allows you to analyze and process large datasets in a fraction of the time. The Databricks Associate Developer Apache Spark Exam will help you master the skills required to build data-driven applications using Apache Spark.

 

QUESTION 87
Which of the following code blocks applies the Python function to_limit on column predError in table transactionsDf, returning a DataFrame with columns transactionId and result?

 
 
 
 
Explanation
spark.udf.register(“LIMIT_FCN”, to_limit)
spark.sql(“SELECT transactionId, LIMIT_FCN(predError) AS result FROM transactionsDf”) Correct! First, you have to register to_limit as UDF to use it in a sql statement. Then, you can use it under the LIMIT_FCN name, correctly naming the resulting column result.
spark.udf.register(to_limit, “LIMIT_FCN”)
spark.sql(“SELECT transactionId, LIMIT_FCN(predError) AS result FROM transactionsDf”) No. In this answer, the arguments to spark.udf.register are flipped.
spark.udf.register(“LIMIT_FCN”, to_limit)
spark.sql(“SELECT transactionId, to_limit(predError) AS result FROM transactionsDf”) Wrong, this answer does not use the registered LIMIT_FCN in the sql statement, but tries to access the to_limit method directly. This will fail, since Spark cannot access it.
spark.sql(“SELECT transactionId, udf(to_limit(predError)) AS result FROM transactionsDf”) Incorrect, there is no udf method in Spark’s SQL.
spark.udf.register(“LIMIT_FCN”, to_limit)
spark.sql(“SELECT transactionId, LIMIT_FCN(predError) FROM transactionsDf AS result”) False. In this answer, the column that results from applying the UDF is not correctly renamed to result.
Static notebook | Dynamic notebook: See test 3

QUESTION 88
The code block displayed below contains an error. The code block should write DataFrame transactionsDf as a parquet file to location filePath after partitioning it on column storeId. Find the error.
Code block:
transactionsDf.write.partitionOn(“storeId”).parquet(filePath)

 
 
 
 
 
Explanation
No method partitionOn() exists for the DataFrame class, partitionBy() should be used instead.
Correct! Find out more about partitionBy() in the documentation (linked below).
The operator should use the mode() option to configure the DataFrameWriter so that it replaces any existing files at location filePath.
No. There is no information about whether files should be overwritten in the question.
The partitioning column as well as the file path should be passed to the write() method of DataFrame transactionsDf directly and not as appended commands as in the code block.
Incorrect. To write a DataFrame to disk, you need to work with a DataFrameWriter object which you get access to through the DataFrame.writer property – no parentheses involved.
Column storeId should be wrapped in a col() operator.
No, this is not necessary – the problem is in the partitionOn command (see above).
The partitionOn method should be called before the write method.
Wrong. First of all partitionOn is not a valid method of DataFrame. However, even assuming partitionOn would be replaced by partitionBy (which is a valid method), this method is a method of DataFrameWriter and not of DataFrame. So, you would always have to first call DataFrame.write to get access to the DataFrameWriter object and afterwards call partitionBy.
More info: pyspark.sql.DataFrameWriter.partitionBy – PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 3

QUESTION 89
The code block displayed below contains an error. The code block below is intended to add a column itemNameElements to DataFrame itemsDf that includes an array of all words in column itemName. Find the error.
Sample of DataFrame itemsDf:
1.+——+———————————-+——————-+
2.|itemId|itemName |supplier |
3.+——+———————————-+——————-+
4.|1 |Thick Coat for Walking in the Snow|Sports Company Inc.|
5.|2 |Elegant Outdoors Summer Dress |YetiX |
6.|3 |Outdoors Backpack |Sports Company Inc.|
7.+——+———————————-+——————-+
Code block:
itemsDf.withColumnRenamed(“itemNameElements”, split(“itemName”))
itemsDf.withColumnRenamed(“itemNameElements”, split(“itemName”))

 
 
 
 
 
Explanation
Correct code block:
itemsDf.withColumn(“itemNameElements”, split(“itemName”,” “))
Output of code block:
+——+———————————-+——————-+——————————————+
|itemId|itemName |supplier |itemNameElements |
+——+———————————-+——————-+——————————————+
|1 |Thick Coat for Walking in the Snow|Sports Company Inc.|[Thick, Coat, for, Walking, in, the, Snow]|
|2 |Elegant Outdoors Summer Dress |YetiX |[Elegant, Outdoors, Summer, Dress] |
|3 |Outdoors Backpack |Sports Company Inc.|[Outdoors, Backpack] |
+——+———————————-+——————-+——————————————+ The key to solving this question is that the split method definitely needs a second argument here (also look at the link to the documentation below). Given the values in column itemName in DataFrame itemsDf, this should be a space character ” “. This is the character we need to split the words in the column.
More info: pyspark.sql.functions.split – PySpark 3.1.1 documentation
Static notebook | Dynamic notebook: See test 1

QUESTION 90
Which of the following code blocks shows the structure of a DataFrame in a tree-like way, containing both column names and types?

 
 
 
 
 
Explanation
itemsDf.printSchema()
Correct! Here is an example of what itemsDf.printSchema() shows, you can see the tree-like structure containing both column names and types:
root
|– itemId: integer (nullable = true)
|– attributes: array (nullable = true)
| |– element: string (containsNull = true)
|– supplier: string (nullable = true)
itemsDf.rdd.printSchema()
No, the DataFrame’s underlying RDD does not have a printSchema() method.
spark.schema(itemsDf)
Incorrect, there is no spark.schema command.
print(itemsDf.columns)
print(itemsDf.dtypes)
Wrong. While the output of this code blocks contains both column names and column types, the information is not arranges in a tree-like way.
itemsDf.print.schema()
No, DataFrame does not have a print method.
Static notebook | Dynamic notebook: See test 3

QUESTION 91
Which of the following code blocks displays various aggregated statistics of all columns in DataFrame transactionsDf, including the standard deviation and minimum of values in each column?

 
 
 
 
 
Explanation
The DataFrame.summary() command is very practical for quickly calculating statistics of a DataFrame. You need to call .show() to display the results of the calculation. By default, the command calculates various statistics (see documentation linked below), including standard deviation and minimum.
Note that the answer that lists many options in the summary() parentheses does not include the minimum, which is asked for in the question.
Answer options that include agg() do not work here as shown, since DataFrame.agg() expects more complex, column-specific instructions on how to aggregate values.
More info:
– pyspark.sql.DataFrame.summary – PySpark 3.1.2 documentation
– pyspark.sql.DataFrame.agg – PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 3

QUESTION 92
The code block shown below should return only the average prediction error (column predError) of a random subset, without replacement, of approximately 15% of rows in DataFrame transactionsDf. Choose the answer that correctly fills the blanks in the code block to accomplish this.
transactionsDf.__1__(__2__, __3__).__4__(avg(‘predError’))

 
 
 
 
 
Explanation
Correct code block:
transactionsDf.sample(withReplacement=False, fraction=0.15).select(avg(‘predError’)) You should remember that getting a random subset of rows means sampling. This, in turn should point you to the DataFrame.sample() method. Once you know this, you can look up the correct order of arguments in the documentation (link below).
Lastly, you have to decide whether to use filter, where or select. where is just an alias for filter(). filter() is not the correct method to use here, since it would only allow you to filter rows based on some condition. However, the question asks to return only the average prediction error. You can control the columns that a query returns with the select() method – so this is the correct method to use here.
More info: pyspark.sql.DataFrame.sample – PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 2

QUESTION 93
Which of the following describes the difference between client and cluster execution modes?

 
 
 
 
 
Explanation
In cluster mode, the driver runs on the master node, while in client mode, the driver runs on a virtual machine in the cloud.
This is wrong, since execution modes do not specify whether workloads are run in the cloud or on-premise.
In cluster mode, each node will launch its own executor, while in client mode, executors will exclusively run on the client machine.
Wrong, since in both cases executors run on worker nodes.
In cluster mode, the driver runs on the edge node, while the client mode runs the driver in a worker node.
Wrong – in cluster mode, the driver runs on a worker node. In client mode, the driver runs on the client machine.
In client mode, the cluster manager runs on the same host as the driver, while in cluster mode, the cluster manager runs on a separate node.
No. In both modes, the cluster manager is typically on a separate node – not on the same host as the driver. It only runs on the same host as the driver in local execution mode.
More info: Learning Spark, 2nd Edition, Chapter 1, and Spark: The Definitive Guide, Chapter 15. ()

QUESTION 94
Which of the following code blocks reads in the two-partition parquet file stored at filePath, making sure all columns are included exactly once even though each partition has a different schema?
Schema of first partition:
1.root
2. |– transactionId: integer (nullable = true)
3. |– predError: integer (nullable = true)
4. |– value: integer (nullable = true)
5. |– storeId: integer (nullable = true)
6. |– productId: integer (nullable = true)
7. |– f: integer (nullable = true)
Schema of second partition:
1.root
2. |– transactionId: integer (nullable = true)
3. |– predError: integer (nullable = true)
4. |– value: integer (nullable = true)
5. |– storeId: integer (nullable = true)
6. |– rollId: integer (nullable = true)
7. |– f: integer (nullable = true)
8. |– tax_id: integer (nullable = false)

 
 
 
 
 
Explanation
This is a very tricky question and involves both knowledge about merging as well as schemas when reading parquet files.
spark.read.option(“mergeSchema”, “true”).parquet(filePath)
Correct. Spark’s DataFrameReader’s mergeSchema option will work well here, since columns that appear in both partitions have matching data types. Note that mergeSchema would fail if one or more columns with the same name that appear in both partitions would have different data types.
spark.read.parquet(filePath)
Incorrect. While this would read in data from both partitions, only the schema in the parquet file that is read in first would be considered, so some columns that appear only in the second partition (e.g. tax_id) would be lost.
nx = 0
for file in dbutils.fs.ls(filePath):
if not file.name.endswith(“.parquet”):
continue
df_temp = spark.read.parquet(file.path)
if nx == 0:
df = df_temp
else:
df = df.union(df_temp)
nx = nx+1
df
Wrong. The key idea of this solution is the DataFrame.union() command. While this command merges all data, it requires that both partitions have the exact same number of columns with identical data types.
spark.read.parquet(filePath, mergeSchema=”y”)
False. While using the mergeSchema option is the correct way to solve this problem and it can even be called with DataFrameReader.parquet() as in the code block, it accepts the value True as a boolean or string variable. But ‘y’ is not a valid option.
nx = 0
for file in dbutils.fs.ls(filePath):
if not file.name.endswith(“.parquet”):
continue
df_temp = spark.read.parquet(file.path)
if nx == 0:
df = df_temp
else:
df = df.join(df_temp, how=”outer”)
nx = nx+1
df
No. This provokes a full outer join. While the resulting DataFrame will have all columns of both partitions, columns that appear in both partitions will be duplicated – the question says all columns that are included in the partitions should appear exactly once.
More info: Merging different schemas in Apache Spark | by Thiago Cordon | Data Arena | Medium Static notebook | Dynamic notebook: See test 3

QUESTION 95
The code block shown below should store DataFrame transactionsDf on two different executors, utilizing the executors’ memory as much as possible, but not writing anything to disk. Choose the answer that correctly fills the blanks in the code block to accomplish this.
1.from pyspark import StorageLevel
2.transactionsDf.__1__(StorageLevel.__2__).__3__

 
 
 
 
 
Explanation
Correct code block:
from pyspark import StorageLevel
transactionsDf.persist(StorageLevel.MEMORY_ONLY_2).count()
Only persist takes different storage levels, so any option using cache() cannot be correct. persist() is evaluated lazily, so an action needs to follow this command. select() is not an action, but count() is – so all options using select() are incorrect.
Finally, the question states that “the executors’ memory should be utilized as much as possible, but not writing anything to disk”. This points to a MEMORY_ONLY storage level. In this storage level, partitions that do not fit into memory will be recomputed when they are needed, instead of being written to disk, as with the storage option MEMORY_AND_DISK. Since the data need to be duplicated across two executors, _2 needs to be appended to the storage level.
Static notebook | Dynamic notebook: See test 2

QUESTION 96
The code block shown below should return a two-column DataFrame with columns transactionId and supplier, with combined information from DataFrames itemsDf and transactionsDf. The code block should merge rows in which column productId of DataFrame transactionsDf matches the value of column itemId in DataFrame itemsDf, but only where column storeId of DataFrame transactionsDf does not match column itemId of DataFrame itemsDf. Choose the answer that correctly fills the blanks in the code block to accomplish this.
Code block:
transactionsDf.__1__(itemsDf, __2__).__3__(__4__)

 
 
 
 
 
Explanation
This question is pretty complex and, in its complexity, is probably above what you would encounter in the exam. However, reading the question carefully, you can use your logic skills to weed out the wrong answers here.
First, you should examine the join statement which is common to all answers. The first argument of the join() operator (documentation linked below) is the DataFrame to be joined with. Where join is in gap 3, the first argument of gap 4 should therefore be another DataFrame. For none of the questions where join is in the third gap, this is the case. So you can immediately discard two answers.
For all other answers, join is in gap 1, followed by .(itemsDf, according to the code block. Given how the join() operator is called, there are now three remaining candidates.
Looking further at the join() statement, the second argument (on=) expects “a string for the join column name, a list of column names, a join expression (Column), or a list of Columns”, according to the documentation. As one answer option includes a list of join expressions (transactionsDf.productId==itemsDf.itemId, transactionsDf.storeId!=itemsDf.itemId) which is unsupported according to the documentation, we can discard that answer, leaving us with two remaining candidates.
Both candidates have valid syntax, but only one of them fulfills the condition in the question “only where column storeId of DataFrame transactionsDf does not match column itemId of DataFrame itemsDf”. So, this one remaining answer option has to be the correct one!
As you can see, although sometimes overwhelming at first, even more complex questions can be figured out by rigorously applying the knowledge you can gain from the documentation during the exam.
More info: pyspark.sql.DataFrame.join – PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 3

QUESTION 97
Which of the following statements about Spark’s execution hierarchy is correct?

 
 
 
 
 
Explanation
In Spark’s execution hierarchy, a job may reach over multiple stage boundaries.
Correct. A job is a sequence of stages, and thus may reach over multiple stage boundaries.
In Spark’s execution hierarchy, tasks are one layer above slots.
Incorrect. Slots are not a part of the execution hierarchy. Tasks are the lowest layer.
In Spark’s execution hierarchy, a stage comprises multiple jobs.
No. It is the other way around – a job consists of one or multiple stages.
In Spark’s execution hierarchy, executors are the smallest unit.
False. Executors are not a part of the execution hierarchy. Tasks are the smallest unit!
In Spark’s execution hierarchy, manifests are one layer above jobs.
Wrong. Manifests are not a part of the Spark ecosystem.

QUESTION 98
Which of the following statements about RDDs is incorrect?

 
 
 
 
 
Explanation
An RDD consists of a single partition.
Quite the opposite: Spark partitions RDDs and distributes the partitions across multiple nodes.

QUESTION 99
Which of the following statements about garbage collection in Spark is incorrect?

 
 
 
 
 
Explanation
Manually persisting RDDs in Spark prevents them from being garbage collected.
This statement is incorrect, and thus the correct answer to the question. Spark’s garbage collector will remove even persisted objects, albeit in an “LRU” fashion. LRU stands for least recently used.
So, during a garbage collection run, the objects that were used the longest time ago will be garbage collected first.
See the linked StackOverflow post below for more information.
Serialized caching is a strategy to increase the performance of garbage collection.
This statement is correct. The more Java objects Spark needs to collect during garbage collection, the longer it takes. Storing a collection of many Java objects, such as a DataFrame with a complex schema, through serialization as a single byte array thus increases performance. This means that garbage collection takes less time on a serialized DataFrame than an unserialized DataFrame.
Optimizing garbage collection performance in Spark may limit caching ability.
This statement is correct. A full garbage collection run slows down a Spark application. When taking about
“tuning” garbage collection, we mean reducing the amount or duration of these slowdowns.
A full garbage collection run is triggered when the Old generation of the Java heap space is almost full. (If you are unfamiliar with this concept, check out the link to the Garbage Collection Tuning docs below.) Thus, one measure to avoid triggering a garbage collection run is to prevent the Old generation share of the heap space to be almost full.
To achieve this, one may decrease its size. Objects with sizes greater than the Old generation space will then be discarded instead of cached (stored) in the space and helping it to be “almost full”.
This will decrease the number of full garbage collection runs, increasing overall performance.
Inevitably, however, objects will need to be recomputed when they are needed. So, this mechanism only works when a Spark application needs to reuse cached data as little as possible.
Garbage collection information can be accessed in the Spark UI’s stage detail view.
This statement is correct. The task table in the Spark UI’s stage detail view has a “GC Time” column, indicating the garbage collection time needed per task.
In Spark, using the G1 garbage collector is an alternative to using the default Parallel garbage collector.
This statement is correct. The G1 garbage collector, also known as garbage first garbage collector, is an alternative to the default Parallel garbage collector.
While the default Parallel garbage collector divides the heap into a few static regions, the G1 garbage collector divides the heap into many small regions that are created dynamically. The G1 garbage collector has certain advantages over the Parallel garbage collector which improve performance particularly for Spark workloads that require high throughput and low latency.
The G1 garbage collector is not enabled by default, and you need to explicitly pass an argument to Spark to enable it. For more information about the two garbage collectors, check out the Databricks article linked below.

QUESTION 100
The code block displayed below contains an error. The code block is intended to write DataFrame transactionsDf to disk as a parquet file in location /FileStore/transactions_split, using column storeId as key for partitioning. Find the error.
Code block:
transactionsDf.write.format(“parquet”).partitionOn(“storeId”).save(“/FileStore/transactions_split”)A.

 
 
 
 
 
Explanation
Correct code block:
transactionsDf.write.format(“parquet”).partitionBy(“storeId”).save(“/FileStore/transactions_split”) More info: partition by – Reading files which are written using PartitionBy or BucketBy in Spark – Stack Overflow Static notebook | Dynamic notebook: See test 1

QUESTION 101
Which of the following code blocks creates a new DataFrame with 3 columns, productId, highest, and lowest, that shows the biggest and smallest values of column value per value in column productId from DataFrame transactionsDf?
Sample of DataFrame transactionsDf:
1.+————-+———+—–+——-+———+—-+
2.|transactionId|predError|value|storeId|productId| f|
3.+————-+———+—–+——-+———+—-+
4.| 1| 3| 4| 25| 1|null|
5.| 2| 6| 7| 2| 2|null|
6.| 3| 3| null| 25| 3|null|
7.| 4| null| null| 3| 2|null|
8.| 5| null| null| null| 2|null|
9.| 6| 3| 2| 25| 2|null|
10.+————-+———+—–+——-+———+—-+

 
 
 
 
 
Explanation
transactionsDf.groupby(‘productId’).agg(max(‘value’).alias(‘highest’), min(‘value’).alias(‘lowest’)) Correct. groupby and aggregate is a common pattern to investigate aggregated values of groups.
transactionsDf.groupby(“productId”).agg({“highest”: max(“value”), “lowest”: min(“value”)}) Wrong. While DataFrame.agg() accepts dictionaries, the syntax of the dictionary in this code block is wrong.
If you use a dictionary, the syntax should be like {“value”: “max”}, so using the column name as the key and the aggregating function as value.
transactionsDf.agg(max(‘value’).alias(‘highest’), min(‘value’).alias(‘lowest’)) Incorrect. While this is valid Spark syntax, it does not achieve what the question asks for. The question specifically asks for values to be aggregated per value in column productId – this column is not considered here. Instead, the max() and min() values are calculated as if the entire DataFrame was a group.
transactionsDf.max(‘value’).min(‘value’)
Wrong. There is no DataFrame.max() method in Spark, so this command will fail.
transactionsDf.groupby(col(productId)).agg(max(col(value)).alias(“highest”), min(col(value)).alias(“lowest”)) No. While this may work if the column names are expressed as strings, this will not work as is. Python will interpret the column names as variables and, as a result, pySpark will not understand which columns you want to aggregate.
More info: pyspark.sql.DataFrame.agg – PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 3

QUESTION 102
Which of the following is the deepest level in Spark’s execution hierarchy?

 
 
 
 
 
Explanation
The hierarchy is, from top to bottom: Job, Stage, Task.
Executors and slots facilitate the execution of tasks, but they are not directly part of the hierarchy. Executors are launched by the driver on worker nodes for the purpose of running a specific Spark application. Slots help Spark parallelize work. An executor can have multiple slots which enable it to process multiple tasks in parallel.

QUESTION 103
The code block shown below should return a one-column DataFrame where the column storeId is converted to string type. Choose the answer that correctly fills the blanks in the code block to accomplish this.
transactionsDf.__1__(__2__.__3__(__4__))

 
 
 
 
 
Explanation
Correct code block:
transactionsDf.select(col(“storeId”).cast(StringType()))
Solving this question involves understanding that, when using types from the pyspark.sql.types such as StringType, these types need to be instantiated when using them in Spark, or, in simple words, they need to be followed by parentheses like so: StringType(). You could also use .cast(“string”) instead, but that option is not given here.
More info: pyspark.sql.Column.cast – PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 2

QUESTION 104
Which of the following statements about DAGs is correct?

 
 
 
 
 
Explanation
DAG stands for “Directing Acyclic Graph”.
No, DAG stands for “Directed Acyclic Graph”.
Spark strategically hides DAGs from developers, since the high degree of automation in Spark means that developers never need to consider DAG layouts.
No, quite the opposite. You can access DAGs through the Spark UI and they can be of great help when optimizing queries manually.
In contrast to transformations, DAGs are never lazily executed.
DAGs represent the execution plan in Spark and as such are lazily executed when the driver requests the data processed in the DAG.

QUESTION 105
Which of the following code blocks returns DataFrame transactionsDf sorted in descending order by column predError, showing missing values last?

 
 
 
 
 
Explanation
transactionsDf.sort(“predError”, ascending=False)
Correct! When using DataFrame.sort() and setting ascending=False, the DataFrame will be sorted by the specified column in descending order, putting all missing values last. An alternative, although not listed as an answer here, would be transactionsDf.sort(desc_nulls_last(“predError”)).
transactionsDf.sort(asc_nulls_last(“predError”))
Incorrect. While this is valid syntax, the DataFrame will be sorted on column predError in ascending order and not in descending order, putting missing values last.
transactionsDf.desc_nulls_last(“predError”)
Wrong, this is invalid syntax. There is no method DataFrame.desc_nulls_last() in the Spark API. There is a Spark function desc_nulls_last() however (link see below).
transactionsDf.orderBy(“predError”).desc_nulls_last()
No. While transactionsDf.orderBy(“predError”) is correct syntax (although it sorts the DataFrame by column predError in ascending order) and returns a DataFrame, there is no method DataFrame.desc_nulls_last() in the Spark API. There is a Spark function desc_nulls_last() however (link see below).
transactionsDf.orderBy(“predError”).asc_nulls_last()
Incorrect. There is no method DataFrame.asc_nulls_last() in the Spark API (see above).
More info: pyspark.sql.functions.desc_nulls_last – PySpark 3.1.2 documentation and pyspark.sql.DataFrame.sort – PySpark 3.1.2 documentation (https://bit.ly/3g1JtbI , https://bit.ly/2R90NCS) Static notebook | Dynamic notebook: See test 1 (https://flrs.github.io/spark_practice_tests_code/#1/32.html ,
https://bit.ly/sparkpracticeexams_import_instructions)

QUESTION 106
Which of the following code blocks returns the number of unique values in column storeId of DataFrame transactionsDf?

 
 
 
 
 
Explanation
transactionsDf.select(“storeId”).dropDuplicates().count()
Correct! After dropping all duplicates from column storeId, the remaining rows get counted, representing the number of unique values in the column.
transactionsDf.select(count(“storeId”)).dropDuplicates()
No. transactionsDf.select(count(“storeId”)) just returns a single-row DataFrame showing the number of non-null rows. dropDuplicates() does not have any effect in this context.
transactionsDf.dropDuplicates().agg(count(“storeId”))
Incorrect. While transactionsDf.dropDuplicates() removes duplicate rows from transactionsDf, it does not do so taking only column storeId into consideration, but eliminates full row duplicates instead.
transactionsDf.distinct().select(“storeId”).count()
Wrong. transactionsDf.distinct() identifies unique rows across all columns, but not only unique rows with respect to column storeId. This may leave duplicate values in the column, making the count not represent the number of unique values in that column.
transactionsDf.select(distinct(“storeId”)).count()
False. There is no distinct method in pyspark.sql.functions.

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